How many gram of oxygen `(O_(2))` is required to completely react with 0.200 g of hydrogen `(H_(2))` to yield water `(H_(2)O)` ? Also calculate the amount of water formed (molecular mass H = 2, O = 32).

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction between hydrogen and oxygen to form water is:
\[ 2H_2 + O_2 \rightarrow 2H_2O \]

### Step 2: Calculate the number of moles of hydrogen (H₂)
Given the mass of hydrogen (H₂) is 0.200 g, we can calculate the number of moles using the formula:
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