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500 ml of 0.1 M AlCl(3) is mixed with 50...

500 ml of `0.1 M AlCl_(3)` is mixed with 500 ml of `0.1 M MgCl_(2)` solution. Then calculation the molarity of `Cl^(-)` in final solution.

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To solve the problem of calculating the molarity of \( Cl^- \) in the final solution after mixing 500 ml of \( 0.1 M \) \( AlCl_3 \) with 500 ml of \( 0.1 M \) \( MgCl_2 \), we can follow these steps: ### Step 1: Calculate the number of millimoles of \( AlCl_3 \) The formula to calculate the number of millimoles is: \[ \text{Millimoles} = \text{Molarity} \times \text{Volume (in mL)} \] For \( AlCl_3 \): ...
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