Calculate the normality of HCl solution whose 500 ml is utillised to neutralise the 1500 ml of `(N)/(10)` NaOH solution.

Explanation

To calculate the normality of the HCl solution, we will use the relationship between the normalities and volumes of the acid and base involved in the neutralization reaction.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Volume of HCl solution (V1) = 500 ml
- Volume of NaOH solution (V2) = 1500 ml
- Normality of NaOH solution (N2) = \( \frac{N}{10} = 0.1 \, N \)
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