Home
Class 12
CHEMISTRY
Convert the following in kilogram. (i)...

Convert the following in kilogram.
(i) `0.91xx10^(-27)g` (Mass of electron)
(ii) `3.34xx10^(-24)g` (Mass of hydrogen molecule)

Text Solution

AI Generated Solution

The correct Answer is:
To convert the given masses from grams to kilograms, we can follow these steps: ### Step 1: Understand the Conversion Factor 1 kilogram (kg) is equal to 1000 grams (g). Therefore, to convert grams to kilograms, we can use the conversion factor: \[ 1 \text{ g} = 10^{-3} \text{ kg} \] ### Step 2: Convert the Mass of the Electron The mass of the electron is given as: \[ 0.91 \times 10^{-27} \text{ g} \] To convert this to kilograms: \[ \text{Mass of electron in kg} = 0.91 \times 10^{-27} \text{ g} \times 10^{-3} \text{ kg/g} \] \[ = 0.91 \times 10^{-30} \text{ kg} \] ### Step 3: Simplify the Expression We can express \( 0.91 \times 10^{-30} \) in scientific notation: \[ = 9.1 \times 10^{-31} \text{ kg} \] ### Step 4: Convert the Mass of the Hydrogen Molecule The mass of the hydrogen molecule is given as: \[ 3.34 \times 10^{-24} \text{ g} \] To convert this to kilograms: \[ \text{Mass of hydrogen molecule in kg} = 3.34 \times 10^{-24} \text{ g} \times 10^{-3} \text{ kg/g} \] \[ = 3.34 \times 10^{-27} \text{ kg} \] ### Final Answers 1. The mass of the electron in kilograms is: \[ 9.1 \times 10^{-31} \text{ kg} \] 2. The mass of the hydrogen molecule in kilograms is: \[ 3.34 \times 10^{-27} \text{ kg} \] ---
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION A (Objective Type Questions (One option is correct))|46 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION B (Objective Type Questions (One option is correct))|25 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challenges Questions)|10 Videos
  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos
  • STATES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the number of g-molecules (mole of molecules) in the following : (i) 3.2 gm CH_(4) (ii) 70 gm nitrogen (iii) 4.5xx10^(24) molecules of ozone (iv) 2.4xx10^(21) atoms of hydrogen (v) 11.2 L ideal gas at 0^(@) C and 1 atm (vi) 4.54 ml SO_(3) gas at STP (vii) 8.21 L C_(2)H_(6) gas at 400 K and 2 atm (viii) 164.2 ml He gas at 27^(@)C and 570 torr [N_(A)=6xx10^(23)]

Express each of the following in kilograms a) 5.84 xx 10^(-3) mg b) 58.34 g c) 0.584 g d) 5.873 xx 10^(-21) g

The kinetic energy of an electron is 4.55 xx 10^(-25) J .The mass of electron is 9.1 xx 10^(-34) kg . Calculate velocity of the electron.

Compare the following numbers : (i) 27 xx 10^12, 15 xx 10^8 (ii) 4 xx 10^14, 3 xx 10^17

Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron = 1.6725 xx 10^(-27) kg mass of proton = 1.6725 xx 10^(-27) kg mass of electron = 9 xx 10^(-31) kg )

Mass of one atom of an element is 3.64× 10^(−24) g. This is equal to :

The speed of the electron in the hydrogen atom is approximately 2.2 xx 10^(6) m//s . What is the centripetal force acting on the electron ifthe radius of the circular orbit is 0.53 xx 10^(-10) m ?Mass of the electron is 9.1 xx 10^(-31) kg

Mass of one atom of an element is 8.46× 10^(−24) g. This is equal to :

Mass of one atom of an element is 6.64× 10^(−24) g. This is equal to :

Mass of one atom of an element is 7.64× 10^(−24) g. This is equal to :

AAKASH INSTITUTE ENGLISH-SOME BASIC CONCEPTS OF CHEMISTRY -TRY YOURSELF
  1. Perform the following calculations to the appropriate number of signfi...

    Text Solution

    |

  2. Perform the following calculations to the appropriate number of signfi...

    Text Solution

    |

  3. Convert the following in kilogram. (i) 0.91xx10^(-27)g (Mass of elec...

    Text Solution

    |

  4. Density of an object is g//cm^(3). Express it in kg//m^(3).

    Text Solution

    |

  5. When 6.4 g of NaHCO(3) is added to a solution of CH(3)COOH weighing 20...

    Text Solution

    |

  6. If 12.6 g of NaHCO(3) are added to 30.0 g of CH(3)COOH solution, the r...

    Text Solution

    |

  7. 2.75 g of cupric oxide was reduced by heating in a current of hydrogen...

    Text Solution

    |

  8. 12.976 g of lead combines with 2.004 g of oxygen to form PbO(2). PbO(2...

    Text Solution

    |

  9. On analysis it was found that the black oxide of copper and red oxide ...

    Text Solution

    |

  10. Sulphur and oxygen are known to form two compounds. The sulphur conten...

    Text Solution

    |

  11. Boron has two isotopes, B-10 and B-11. The average atomic mass of boro...

    Text Solution

    |

  12. Carbon found nature as a mixture of C-12 and C-13. The average atomic ...

    Text Solution

    |

  13. Calculate the molar mass of the following: (i) H(2)O (ii) CO(2) (i...

    Text Solution

    |

  14. Find the molecular mass of glucose (C6H12O6) and calculate the mass of...

    Text Solution

    |

  15. Calculate mass of one atom of calcium in gram.

    Text Solution

    |

  16. Calculate mass of one molecule of sulphur dioxide (SO(2)) in gram.

    Text Solution

    |

  17. Calculate number of atoms in 0.5 mole of oxygen atoms.

    Text Solution

    |

  18. Calculate number of atoms in 0.2 mole of oxygen atoms.

    Text Solution

    |

  19. Calculate percentage of sulphur in sulphuric acid (H(2)SO(4)).

    Text Solution

    |

  20. Calculate percentage of carbon in ethanol (C(2)H(5)OH).

    Text Solution

    |