Calculate the molality of a solution containing 8 moles of sucrose in 250 g of solvent.

Answer

To calculate the molality of a solution containing 8 moles of sucrose in 250 g of solvent, we can follow these steps:

### Step 1: Understand the definition of molality
Molality (m) is defined as the number of moles of solute per kilogram of solvent. The formula for molality is:

\[ \text{Molality (m)} = \frac{\text{Number of moles of solute}}{\text{Mass of solvent in kg}} \]

### Step 2: Identify the given data
From the problem, we have:
- Number of moles of sucrose (solute) = 8 moles
- Mass of solvent = 250 g

### Step 3: Convert the mass of solvent from grams to kilograms
Since molality requires the mass of the solvent in kilograms, we need to convert 250 g to kg:

\[ \text{Mass of solvent in kg} = \frac{250 \text{ g}}{1000 \text{ g/kg}} = 0.25 \text{ kg} \]

### Step 4: Substitute the values into the molality formula
Now, we can substitute the values into the molality formula:

\[ \text{Molality (m)} = \frac{8 \text{ moles}}{0.25 \text{ kg}} \]

### Step 5: Calculate the molality
Now, perform the calculation:

\[ \text{Molality (m)} = \frac{8}{0.25} = 32 \text{ moles/kg} \]

### Final Answer
The molality of the solution is:

\[ \text{Molality} = 32 \text{ moles/kg} \]

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