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Which one of the following samples conta...

Which one of the following samples contains the smallest number of atoms ?

A

1 g of `CO_(2)`

B

1 g of `C_(8) H_(18)`

C

1 g of `C_(2) H_(6)`

D

1 g of LIF

Text Solution

AI Generated Solution

The correct Answer is:
To determine which sample contains the smallest number of atoms, we will calculate the number of atoms in each of the given samples (1 g of CO2, C8H18, C2H6, and LiF) by following these steps: ### Step 1: Calculate the number of moles for each compound 1. **For CO2:** - Molar mass of CO2 = 12 (C) + 16*2 (O) = 44 g/mol - Moles of CO2 = mass / molar mass = 1 g / 44 g/mol = 0.02273 moles 2. **For C8H18:** - Molar mass of C8H18 = 12*8 (C) + 1*18 (H) = 114 g/mol - Moles of C8H18 = 1 g / 114 g/mol = 0.00877 moles 3. **For C2H6:** - Molar mass of C2H6 = 12*2 (C) + 1*6 (H) = 30 g/mol - Moles of C2H6 = 1 g / 30 g/mol = 0.03333 moles 4. **For LiF:** - Molar mass of LiF = 6.94 (Li) + 19 (F) = 26 g/mol - Moles of LiF = 1 g / 26 g/mol = 0.03846 moles ### Step 2: Calculate the number of molecules for each compound Using Avogadro's number (NA = 6.022 x 10^23 molecules/mol): 1. **For CO2:** - Number of molecules = moles × NA = 0.02273 moles × 6.022 x 10^23 = 1.367 x 10^22 molecules 2. **For C8H18:** - Number of molecules = 0.00877 moles × 6.022 x 10^23 = 5.27 x 10^21 molecules 3. **For C2H6:** - Number of molecules = 0.03333 moles × 6.022 x 10^23 = 2.01 x 10^22 molecules 4. **For LiF:** - Number of molecules = 0.03846 moles × 6.022 x 10^23 = 2.31 x 10^22 molecules ### Step 3: Calculate the number of atoms in each compound 1. **For CO2 (3 atoms per molecule):** - Number of atoms = number of molecules × 3 = 1.367 x 10^22 × 3 = 4.10 x 10^22 atoms 2. **For C8H18 (26 atoms per molecule):** - Number of atoms = number of molecules × 26 = 5.27 x 10^21 × 26 = 1.37 x 10^23 atoms 3. **For C2H6 (8 atoms per molecule):** - Number of atoms = number of molecules × 8 = 2.01 x 10^22 × 8 = 1.61 x 10^23 atoms 4. **For LiF (2 atoms per molecule):** - Number of atoms = number of molecules × 2 = 2.31 x 10^22 × 2 = 4.62 x 10^22 atoms ### Step 4: Compare the number of atoms - CO2: 4.10 x 10^22 atoms - C8H18: 1.37 x 10^23 atoms - C2H6: 1.61 x 10^23 atoms - LiF: 4.62 x 10^22 atoms ### Conclusion The sample with the smallest number of atoms is **1 g of CO2**. ---
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