A sample of ammonium phosphate `(NH_(4))_(3) PO_(4)` contains 3.18 moles of hyrogen atoms . The number of moles of oxygen atoms in the sample is

Options

A. `0.265`
B. `0.795`
C. `1.06`
D. `4.00`

Answer

To find the number of moles of oxygen atoms in a sample of ammonium phosphate `(NH₄)₃PO₄` that contains 3.18 moles of hydrogen atoms, we can follow these steps:

### Step 1: Determine the composition of ammonium phosphate
Ammonium phosphate has the formula `(NH₄)₃PO₄`. This means:
- There are 3 moles of nitrogen (N) atoms.
- There are 12 moles of hydrogen (H) atoms (since each ammonium ion `(NH₄)⁺` contributes 4 hydrogen atoms, and there are 3 ammonium ions).
- There is 1 mole of phosphorus (P) atom.
- There are 4 moles of oxygen (O) atoms.

### Step 2: Establish the ratio of hydrogen to oxygen
From the formula, we see that:
- 12 moles of hydrogen correspond to 4 moles of oxygen.

### Step 3: Set up the proportion
We can set up a proportion based on the number of moles of hydrogen and oxygen:
\[ \frac{12 \text{ moles of H}}{4 \text{ moles of O}} = \frac{3.18 \text{ moles of H}}{x \text{ moles of O}} \]
Where \(x\) is the number of moles of oxygen we want to find.

### Step 4: Solve for \(x\)
Cross-multiplying gives us:
\[ 12x = 4 \times 3.18 \]
\[ 12x = 12.72 \]
Now, divide both sides by 12:
\[ x = \frac{12.72}{12} = 1.06 \]

### Conclusion
The number of moles of oxygen atoms in the sample is **1.06 moles**.

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