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The percentage of hydrogen in water and ...

The percentage of hydrogen in water and hydrogen peroxide is 11 .1 and 5.9 respectively . These figures illustrate

A

Law of multiple proportions

B

Law of conservation of mass

C

Law of constant proportions

D

Law of combining volumes

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The correct Answer is:
To solve the question regarding the percentage of hydrogen in water (H2O) and hydrogen peroxide (H2O2), we need to analyze the data provided and relate it to the laws of chemistry. ### Step-by-Step Solution: 1. **Identify the Compounds**: - We have two compounds: water (H2O) and hydrogen peroxide (H2O2). - The percentage of hydrogen in water is given as 11.1%. - The percentage of hydrogen in hydrogen peroxide is given as 5.9%. 2. **Calculate the Mass of Hydrogen in Each Compound**: - For water (H2O): - Molar mass of H2O = (2 × 1) + (16) = 18 g/mol - Percentage of hydrogen = (mass of hydrogen / molar mass of H2O) × 100 - Mass of hydrogen in H2O = (2 g / 18 g) × 100 = 11.1% - For hydrogen peroxide (H2O2): - Molar mass of H2O2 = (2 × 1) + (2 × 16) = 34 g/mol - Percentage of hydrogen = (mass of hydrogen / molar mass of H2O2) × 100 - Mass of hydrogen in H2O2 = (2 g / 34 g) × 100 = 5.9% 3. **Compare the Percentages**: - The percentage of hydrogen in water is significantly higher than in hydrogen peroxide. - Specifically, the percentage of hydrogen in water (11.1%) is approximately double that of hydrogen peroxide (5.9%). 4. **Relate to the Law of Multiple Proportions**: - The law of multiple proportions states that when two elements combine to form more than one compound, the ratios of the masses of one element that combine with a fixed mass of the other element can be expressed in small whole numbers. - Here, hydrogen is combining with oxygen in two different compounds (H2O and H2O2), and the ratios of the percentages of hydrogen can be interpreted as being in a whole number ratio. 5. **Conclusion**: - Since the percentages of hydrogen in these two compounds illustrate the principle that hydrogen can combine with oxygen in different ratios, we conclude that the figures illustrate the **Law of Multiple Proportions**. ### Final Answer: The figures illustrate the **Law of Multiple Proportions** (Option A).
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AAKASH INSTITUTE ENGLISH-SOME BASIC CONCEPTS OF CHEMISTRY -ASSIGNMENT SECTION A (Objective Type Questions (One option is correct))
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  2. Which one of the following best explains the law of conservation of ma...

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  3. The percentage of hydrogen in water and hydrogen peroxide is 11 .1 and...

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  4. Element X forms five stable oxides with oxygen of formula X(2) O, XO ,...

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  5. Which of the following represents Avogadro's hypothesis ?

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  6. Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively...

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  7. Which of the following is not a physical quantity of measurement ?

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  8. Physical properties can be measured

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  9. When 200 g of lime strongly heated , it undergoes thermal decompositio...

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  10. Carbon and oxygen react in ratio 3 : 8 by mass to form CO(2) . What we...

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  11. Molecular mass of C(3) H(7) OH is

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  12. If an atom of an element has twice the mass of C-12 , then its atomic ...

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  13. Formula unit mass of K(2) CO(3) is (Atomic mass of K = 39 u , C = 1...

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  14. The number of moles of nitrogen atom in 56 g nitrogen is

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  15. The number of mole of N - atom in 18.066 x 10 ^(23) nitrogen atoms is

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  16. The number of particles presents in 1 mol of nitrogen atom are

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  17. Molality is expressed in units of

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  18. Which of the following is correct ?

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  19. What weight in grams is represented by 1.5 moles of sulphur dioxide ?

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  20. The number of atoms in 20 g of SO(3) is approximately

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