The number of mole of N - atom in `18.066 x 10 ^(23)` nitrogen atoms is

Options

A. 1 mol
B. 2 mol
C. 3 mol
D. 4 mol

Answer

To find the number of moles of nitrogen atoms in \( 18.066 \times 10^{23} \) nitrogen atoms, we can use the following steps:

### Step 1: Understand the concept of moles
A mole is a unit in chemistry that represents \( 6.022 \times 10^{23} \) entities (atoms, molecules, etc.). This number is known as Avogadro's number.

### Step 2: Write down the formula for calculating moles
The formula to calculate the number of moles (\( n \)) from the number of atoms (\( N \)) is given by:

\[ n = \frac{N}{N_A} \]

where \( N_A \) is Avogadro's number, approximately \( 6.022 \times 10^{23} \).

### Step 3: Substitute the values into the formula
Here, \( N = 18.066 \times 10^{23} \) atoms. Now we can substitute this value into the formula:

\[ n = \frac{18.066 \times 10^{23}}{6.022 \times 10^{23}} \]

### Step 4: Perform the calculation
Now, we can simplify the calculation:

\[ n = \frac{18.066}{6.022} \]

Calculating this gives:

\[ n \approx 3.00 \]

### Step 5: Conclusion
Thus, the number of moles of nitrogen atoms in \( 18.066 \times 10^{23} \) nitrogen atoms is approximately \( 3 \) moles.

### Final Answer
The number of moles of N-atom in \( 18.066 \times 10^{23} \) nitrogen atoms is **3 moles**.

---