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STATEMENT - 1 : Equivalent weight of a s...

STATEMENT - 1 : Equivalent weight of a substance can never be greater than its molecular weight.
STATEMENT - 2 : Equivalent weight of boric acid is `(M)/(1)` where M is the molecular weight.
STATEMENT - 3 : Equivalent weight of `H_(3)PO_(2)` is `(M)/(3)`.

A

TTF

B

TFT

C

FTT

D

TFF

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements given in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement 1 **Statement 1:** Equivalent weight of a substance can never be greater than its molecular weight. **Explanation:** - The equivalent weight (EW) is defined as the molecular weight (MW) divided by the n-factor (EW = MW/n). - The n-factor is always a positive integer (greater than or equal to 1) for acids and bases, as it represents the number of moles of reactive species (like H⁺ or OH⁻) that can be replaced or produced. - Therefore, since n is at least 1, the equivalent weight can be equal to or less than the molecular weight, but it cannot exceed it. **Conclusion:** Statement 1 is **True**. ### Step 2: Evaluate Statement 2 **Statement 2:** Equivalent weight of boric acid is \( \frac{M}{1} \) where M is the molecular weight. **Explanation:** - Boric acid (H₃BO₃) can donate one hydrogen ion (H⁺) in reactions, which means its n-factor is 1. - Using the formula for equivalent weight: \[ \text{Equivalent Weight} = \frac{\text{Molecular Weight}}{\text{n-factor}} = \frac{M}{1} = M \] - Thus, the equivalent weight of boric acid is indeed \( \frac{M}{1} \). **Conclusion:** Statement 2 is **True**. ### Step 3: Evaluate Statement 3 **Statement 3:** Equivalent weight of \( H_3PO_2 \) is \( \frac{M}{3} \). **Explanation:** - To find the equivalent weight of \( H_3PO_2 \) (phosphorous acid), we need to determine its n-factor. - In the case of \( H_3PO_2 \), it can donate two H⁺ ions, so the n-factor is 2. - Therefore, the equivalent weight is calculated as: \[ \text{Equivalent Weight} = \frac{\text{Molecular Weight}}{\text{n-factor}} = \frac{M}{2} \] - The statement claims that the equivalent weight is \( \frac{M}{3} \), which is incorrect. **Conclusion:** Statement 3 is **False**. ### Final Conclusion - **Statement 1:** True - **Statement 2:** True - **Statement 3:** False Thus, the correct option based on the evaluation of the statements is that Statements 1 and 2 are true, while Statement 3 is false.
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