Calcualte the maximum kinetic energy of photoelectrons emitted where as light of freqency `2 xx 10^(16)Hz` is irradiated on a metal surface with threshold frequency `(v_(0))` equal to`8.68 xx10^(15)Hz`.

Explanation

To calculate the maximum kinetic energy of photoelectrons emitted when light of frequency \( \nu = 2 \times 10^{16} \, \text{Hz} \) is irradiated on a metal surface with a threshold frequency \( \nu_0 = 8.68 \times 10^{15} \, \text{Hz} \), we can follow these steps:

### Step 1: Understand the Photoelectric Effect
The photoelectric effect states that when light of a certain frequency shines on a metal surface, electrons are emitted. The energy of the incoming photons is partially used to overcome the work function of the metal, and the remainder is converted into the kinetic energy of the emitted electrons.

### Step 2: Write the Formula
The kinetic energy (KE) of the emitted photoelectrons can be expressed as:
\[
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