An electron is moving in an orbit of circumference 14.92`Å` in `He^(+)` . Calculate
(a) Energy of electron in this orbit
(b) Ionisation Energy of `He^(+)`
(c ) Separation energy

Explanation

To solve the given problem step by step, we will calculate (a) the energy of the electron in the orbit, (b) the ionization energy of \( \text{He}^+ \), and (c) the separation energy.

### Given Data:
- Circumference of the orbit, \( C = 14.92 \, \text{Å} \) (1 Å = \( 10^{-10} \, \text{m} \))
- Atomic number of Helium, \( Z = 2 \)

### Step 1: Calculate the radius of the orbit
The circumference of the orbit is given by the formula:
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