The threshold frequency `v_(0)` for a metal is `8 xx 10^(14) s^(-1)`. What is the kinetic energy of an electron emitted having frequency `v=1.0 xx 10^(15) s^(-1)`

Explanation

To solve the problem of finding the kinetic energy of an emitted electron when given the threshold frequency and the frequency of the incident light, we can use the photoelectric effect equation. Here’s a step-by-step solution:

### Step 1: Understand the Photoelectric Effect Equation
The photoelectric effect is described by the equation:
\[ KE = h\nu - h\nu_0 \]
where:
- \( KE \) is the kinetic energy of the emitted electron,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)),
...