The potential energy of an electron in hydrogen atom is `-3.02 eV`, its kinteic energy will be

Options

A. `1.51 eV`
B. `15.10 eV`
C. ` 13.6 eV`
D. ` 1.36 eV`

Answer

To find the kinetic energy of an electron in a hydrogen atom given its potential energy, we can use the relationship between kinetic energy (KE) and potential energy (PE). The formula we will use is:

\[ KE = -\frac{PE}{2} \]

### Step-by-Step Solution:

1. **Identify the Given Potential Energy (PE)**:
- The potential energy of the electron in the hydrogen atom is given as \( PE = -3.02 \, \text{eV} \).

2. **Apply the Formula for Kinetic Energy (KE)**:
- We substitute the given potential energy into the formula:
\[ KE = -\frac{PE}{2} = -\frac{-3.02 \, \text{eV}}{2} \]

3. **Calculate the Kinetic Energy**:
- Simplifying the equation:
\[ KE = \frac{3.02 \, \text{eV}}{2} = 1.51 \, \text{eV} \]

4. **Conclusion**:
- The kinetic energy of the electron in the hydrogen atom is \( KE = 1.51 \, \text{eV} \).

### Final Answer:
The kinetic energy of the electron is **1.51 eV**.

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