Two hydrogen atoms undergo head on collision and end up with zero kinetic energy. Each particle then emits a photon of wavelength 1028 `Å`. Which transition leads to this wavelength ? Calculate the velocity of hydrogen atom before collision `( m_(H) =1.67 xx 10^(-27) kg)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the Wavelength and Convert to Meters
The wavelength of the emitted photon is given as 1028 Å. We need to convert this into meters for our calculations.

\[ \text{Wavelength} (\lambda) = 1028 \, \text{Å} = 1028 \times 10^{-10} \, \text{m} = 1.028 \times 10^{-7} \, \text{m} \]
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