A swimmer coming out from a pool is covered with a film of water weighing about 18 g. how much heat must be supplied to evaporate this water at 298 K ? Calculate the internal energy of vaperization at `100^(@)C`. `Delta_(vap)H^(Theta)` for water at 373 K = 40.66 kJ `mol^(-1)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the number of moles of water
Given that the weight of water is 18 g, we can calculate the number of moles (n) using the molar mass of water (H₂O), which is approximately 18 g/mol.

\[ n = \frac{\text{mass}}{\text{molar mass}} = \frac{18 \, \text{g}}{18 \, \text{g/mol}} = 1 \, \text{mol} \]
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