Determine enthalpy change for the reaction,
`CH_(4(g))+Cl_(2(g))rarr CH_(3)Cl_((g))+HCl_((g))`
Bond energies for `C-H,C-Cl,Cl-Cl,H-Cl` are `412,338,242,431k J mol^(-1)` respectively.

Explanation

To determine the enthalpy change for the reaction:

\[ \text{CH}_4(g) + \text{Cl}_2(g) \rightarrow \text{CH}_3\text{Cl}(g) + \text{HCl}(g) \]

we will use the bond energies provided for the relevant bonds involved in the reaction. The bond energies are as follows:

- C-H: 412 kJ/mol
- C-Cl: 338 kJ/mol
...