A monoatomic gas undergoes adiabatic process. Its volume and temperature are related as `TV^(P)` = constant. The value of p will be
`{:((1),1.33,(2),1.67),((3),0.67,(4),0.33):}`

Explanation

To solve the problem, we need to find the value of \( p \) in the relationship \( TV^p = \text{constant} \) for a monoatomic gas undergoing an adiabatic process.

### Step-by-Step Solution:

1. **Understanding Adiabatic Processes**:
In an adiabatic process, there is no heat exchange with the surroundings. For an ideal gas, the relationship between temperature \( T \) and volume \( V \) can be expressed as:
\[
TV^{\gamma - 1} = \text{constant}
...