Calculate the weight of gold having specific heat capacity 0.13 J `(.^(@)C)^(-1) g^(-1)` which is heated from `25^(@)C "to" 300^(@)C`, where the heat absorbed is 1500 J.

Explanation

To solve the problem of calculating the weight of gold heated from 25°C to 300°C with a specific heat capacity of 0.13 J/(°C·g) and heat absorbed of 1500 J, we can follow these steps:

### Step 1: Identify the given data
- Specific heat capacity (s) = 0.13 J/(°C·g)
- Initial temperature (T1) = 25°C
- Final temperature (T2) = 300°C
- Heat absorbed (Q) = 1500 J

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