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90 g of water spilled out from a vessel ...

90 g of water spilled out from a vessel in the room on the floor. Assuming that water vapour behaving as an ideal gas, calculate the internal energy change when the spilled water undergoes complete evaporation at `100^(@)C`. (Given the molar enthalpy of vaporisation of water at 1 bar and 373 K = 41 kJ `mol^(-1)`).

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To solve the problem of calculating the internal energy change when 90 g of water evaporates at 100°C, we can follow these steps: ### Step 1: Convert the mass of water to moles To find the number of moles of water, we use the formula: \[ \text{Number of moles} (n) = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] The molar mass of water (H₂O) is approximately 18 g/mol. ...
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Assuming that water vapour is an ideal gas, the internal energy change (Delta U) when 1 mol of water is vapourised at 1 bar pressure and 100^(@)C , (Given: Molar enthalpy of vapourization of water at 1 bar and 373K=41 kJ mol^(-1) and R=8.3J mol^(-1)K^(-1) ) will be:

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