The standard heat of formation of at 298 K for `C Cl_(4)(g), H_(2)O(g), CO_(2)(g) and HCI(g)` are -25.5, -57.8, -94.1 and -22.1 kcal `mol^(-1)` respectively. Calculate `Delta_(r)H^(Theta)` for the reaction
`C Cl_(4)(g)+2H_(2)O(g) rarr CO_(2)(g)+4HCl(g)`
Hint : `Delta_(r)H^(Theta) = sum Delta_(f)H_("Products")^(Theta)- sum Delta_(f)H_("Reactants")^(Theta)`

Explanation

To calculate the standard heat of reaction (Δ_rH°) for the given reaction:

**Reaction:**
\[ \text{CCl}_4(g) + 2 \text{H}_2\text{O}(g) \rightarrow \text{CO}_2(g) + 4 \text{HCl}(g) \]

**Given standard heats of formation (Δ_fH°) at 298 K:**
- Δ_fH° for CCl₄(g) = -25.5 kcal/mol
- Δ_fH° for H₂O(g) = -57.8 kcal/mol
...