A certain reaction is at equilbrium at `82^(@)C and Delta H` for this reaction is 21.3 kJ. What would be the value of `Delta S` (in `JK^(-1)mol^(1)`) for the reaction?

Explanation

To find the value of ΔS (change in entropy) for the reaction at equilibrium, we can follow these steps:

### Step 1: Understand the relationship between ΔG, ΔH, and ΔS
At equilibrium, the change in Gibbs free energy (ΔG) is zero. The relationship is given by the equation:
\[ \Delta G = \Delta H - T \Delta S \]
Since ΔG = 0 at equilibrium, we can rewrite the equation as:
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