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In a chemical reaction, Delta H = 150 kJ...

In a chemical reaction, `Delta H = 150 kJ and Delta S = 100 JK^(-1)` at 300 K. Therefore, `Delta`G will be

A

Zero

B

300 kJ

C

330 kJ

D

120 kJ

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The correct Answer is:
To calculate the Gibbs free energy change (ΔG) for the given reaction, we will use the formula: \[ \Delta G = \Delta H - T \Delta S \] ### Step 1: Identify the given values - ΔH = 150 kJ - ΔS = 100 J/K - T = 300 K ### Step 2: Convert ΔH to the same unit as ΔS Since ΔH is given in kilojoules and ΔS is in joules, we need to convert ΔH to joules for consistency. \[ \Delta H = 150 \text{ kJ} = 150 \times 1000 \text{ J} = 150000 \text{ J} \] ### Step 3: Substitute the values into the Gibbs free energy equation Now we can substitute the values into the equation: \[ \Delta G = 150000 \text{ J} - (300 \text{ K} \times 100 \text{ J/K}) \] ### Step 4: Calculate TΔS Calculate the product of T and ΔS: \[ T \Delta S = 300 \text{ K} \times 100 \text{ J/K} = 30000 \text{ J} \] ### Step 5: Calculate ΔG Now substitute this value back into the equation for ΔG: \[ \Delta G = 150000 \text{ J} - 30000 \text{ J} = 120000 \text{ J} \] ### Step 6: Convert ΔG back to kilojoules Convert ΔG back to kilojoules: \[ \Delta G = \frac{120000 \text{ J}}{1000} = 120 \text{ kJ} \] ### Final Answer Thus, the change in Gibbs free energy (ΔG) is: \[ \Delta G = 120 \text{ kJ} \]
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AAKASH INSTITUTE ENGLISH-THERMODYNAMICS-SECTION-A
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