1 M solution of `CH_(3)COOH` is diluted to x times so that pH of solution is doubled. Calculate x
Given `K_(a)=1.8xx10^(-5)`

Explanation

To solve the problem, we need to determine how much we need to dilute a 1 M solution of acetic acid (CH₃COOH) so that the pH of the solution is doubled. We are given the dissociation constant \( K_a = 1.8 \times 10^{-5} \).

### Step-by-Step Solution:

1. **Calculate pKa:**
\[ pK_a = -\log(K_a) \]
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