Calculate solubility product of `Hg_(2)Cl_(2)` if its solubility at room temperature is `2.0xx10^(-3)mol L^(-1)`

Explanation

To calculate the solubility product (Ksp) of \( \text{Hg}_2\text{Cl}_2 \) given its solubility at room temperature is \( 2.0 \times 10^{-3} \, \text{mol L}^{-1} \), we can follow these steps:

### Step-by-Step Solution:

1. **Write the Dissociation Equation**:
The dissociation of \( \text{Hg}_2\text{Cl}_2 \) in water can be represented as:
\[
\text{Hg}_2\text{Cl}_2 (s) \rightleftharpoons \text{Hg}_2^{2+} (aq) + 2 \text{Cl}^- (aq)
...