The equilibrium constant for the reactio...

The equilibrium constant for the reaction `CaSO_(4).H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g)` is equal to

`([CuSO_(4).5H_(2)O][H_(2)O]^(2))/([CuSO_(4).5H_(2)O])`

`([CuSO_(4).3H_(2)O])/([CuSO_(4).5H_(2)O])`

`[H_(2)O]^(2)`

`[H_(2)O]`

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AAKASH INSTITUTE ENGLISH-EQUILIBRIUM-Assignment (SECTION-A) (SUBJECTIVE TYPE QUESTIONS(ONE OPTION IS CORRECT)

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