If pressure is increased on the equlibrium `N_(2)+O_(2)hArr2NO` the equlibrium will

Options

A. Shift in the forward direction
B. Shift in the backward direction
C. Remain undisturbed
D. None of these

Answer

To solve the question regarding the effect of increased pressure on the equilibrium \( N_2 + O_2 \rightleftharpoons 2NO \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**: The equilibrium reaction given is:
\[ N_2 + O_2 \rightleftharpoons 2NO \]

2. **Count the Moles of Gases**:
- On the **reactant side** (left side), we have:
- 1 mole of \( N_2 \)
- 1 mole of \( O_2 \)
- **Total moles on reactant side** = 1 + 1 = 2 moles
- On the **product side** (right side), we have:
- 2 moles of \( NO \)
- **Total moles on product side** = 2 moles

3. **Apply Le Chatelier's Principle**:
- Le Chatelier's Principle states that if an external change is applied to a system at equilibrium, the system will adjust to counteract that change and restore a new equilibrium.
- In this case, the external change is an **increase in pressure**.

4. **Analyze the Effect of Pressure**:
- When pressure is increased, the equilibrium will shift towards the side with fewer moles of gas to reduce the pressure.
- In our reaction, both sides have the same number of moles (2 moles on the reactant side and 2 moles on the product side).

5. **Conclusion**:
- Since the number of moles of gas is the same on both sides of the equilibrium, increasing the pressure will not favor either side.
- Therefore, the equilibrium will **remain undisturbed**.

### Final Answer:
The equilibrium will remain undisturbed.

---