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At constant pressure, the addition of ar...

At constant pressure, the addition of argon in Haber's process

A

Reduces the formation of ammonia from `N_(2)andH_(2)`

B

Increases the formation of ammonia from `N_(2)and H_(2)`

C

Does not affect the equlibrium of the reaction in which ammonia is formed from `N_(2)and H_(2)`

D

Reduces the dissociation of ammonia

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the effect of adding argon gas at constant pressure in the Haber process, we can follow these steps: ### Step 1: Understand the Haber Process The Haber process is a chemical reaction used to synthesize ammonia (NH3) from nitrogen (N2) and hydrogen (H2). The balanced equation for this reaction is: \[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \] ### Step 2: Identify the Moles of Gases In the balanced equation, we have: - Reactants: 1 mole of N2 + 3 moles of H2 = 4 moles of gas - Products: 2 moles of NH3 ### Step 3: Consider the Effect of Adding Argon Argon is an inert gas, meaning it does not react with the other gases in the reaction. When argon is added at constant pressure, it increases the total number of gas molecules in the system. However, since the pressure is held constant, the volume of the system must change. ### Step 4: Apply Le Chatelier's Principle According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in conditions (such as pressure or volume), the equilibrium will shift in a direction that counteracts that change. In this case, since we are effectively decreasing the volume (to maintain constant pressure with the addition of argon), the equilibrium will shift toward the side with fewer moles of gas to minimize the change. ### Step 5: Determine the Direction of the Shift In our reaction: - The reactants side has 4 moles of gas. - The products side has 2 moles of gas. Since the addition of argon (an inert gas) leads to a decrease in volume, the equilibrium will shift to the left (toward the reactants) to reduce the number of gas moles. ### Step 6: Conclusion As a result, the addition of argon gas reduces the formation of ammonia from nitrogen and hydrogen. Therefore, the correct option is: **Option 1: Reduces the formation of ammonia from N2 and H2.** ---
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AAKASH INSTITUTE ENGLISH-EQUILIBRIUM-Assignment (SECTION-B)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT)
  1. In which of the following does the reaction go almost to completion?

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  2. At constant pressure, the addition of argon in Haber's process

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  3. Consider the general hypothetical reaction A(s)hArr2B(g)+3C(g) If ...

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  4. Pure ammonia is placed in a vessel at a temperature where its dissocia...

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  5. Which of the following is correct if reaction quotient (Q)=1?

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  6. For the equlibrium CO+H(2)OhArrCO(2)+H(2) The relation between K(r...

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  7. What is the vapour density of mixture of PCL(5) at 250^(@)C when it ha...

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  8. The equlibrium constnt (K(rho)) for the reaction, 2SO(2)(g)+O(2)(g)h...

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  9. For the equlibrium H(2)O(s)hArrH(2)O(l) which of the following stateme...

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  10. Conjugate acid of PO(4)^(-3) is

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  11. The dissociation constant of monobasic acids A.B and C are 10^(-4),10^...

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  12. Among the following, which causes the greatest change in pH on additio...

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  13. What will be the H^(+) concentration in a solution prepared by mixing ...

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  14. To 250.0 ml of M//50H(2)SO(4), 4.0 g of solid NaOH is added and the re...

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  15. One "mole" of N(2)O(4)(g) at 300 K is kept in a closed container under...

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  16. For the equlibrium SO(3)(g)hArrSO(2)(g)+1/2O(2)(g) the molar mass at e...

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  17. When a solution of benzoic acid was titrated with NaOH the pH of the s...

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  18. If an aqueous solution at 25^(@)C has twice as many OH^(-) as pure wat...

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  19. Let the solubilities of AgCI in H(2)O, and in 0.01M CaCI(2), 0.01M NaC...

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  20. pH of saturated solution of Ba(OH)(2) is 12. The value of solubility p...

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