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STATEMENT-1: Solubility of BaSO(4) in 0....

STATEMENT-1: Solubility of `BaSO_(4)` in 0.1 M `Na_(2)SO_(4)is 10^(-9)` M hence its `K_(sp)` is `10^(-18).`
STATEMENT-2: In aqueous solution, solubility product of `BaSO_(4)=S^(2).` (Where S is solubility of `BaSO_(4)`)

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to evaluate the two statements provided regarding the solubility product (Ksp) of barium sulfate (BaSO₄). ### Step-by-Step Solution: **Step 1: Analyze Statement 1** - The statement claims that the solubility of BaSO₄ in 0.1 M Na₂SO₄ is \(10^{-9}\) M and that its Ksp is \(10^{-18}\). - When BaSO₄ dissolves, it dissociates into Ba²⁺ and SO₄²⁻ ions: \[ \text{BaSO}_4 (s) \rightleftharpoons \text{Ba}^{2+} (aq) + \text{SO}_4^{2-} (aq) \] **Step 2: Calculate the Effective Concentration of SO₄²⁻** - In a 0.1 M Na₂SO₄ solution, Na₂SO₄ dissociates to give 0.1 M SO₄²⁻ ions: \[ \text{Na}_2\text{SO}_4 \rightarrow 2 \text{Na}^+ + \text{SO}_4^{2-} \] - Therefore, the total concentration of SO₄²⁻ ions in the solution is: \[ [\text{SO}_4^{2-}] = 0.1 \, \text{M} + 10^{-9} \, \text{M} \approx 0.1 \, \text{M} \] (since \(10^{-9}\) M is negligible compared to 0.1 M). **Step 3: Calculate Ksp** - The solubility product expression for BaSO₄ is: \[ K_{sp} = [\text{Ba}^{2+}][\text{SO}_4^{2-}] \] - Substituting the values: \[ K_{sp} = (10^{-9})(0.1) = 10^{-10} \] - The statement claims \(K_{sp} = 10^{-18}\), which is incorrect. **Conclusion for Statement 1:** - Statement 1 is **false**. --- **Step 4: Analyze Statement 2** - The second statement claims that in aqueous solution, the solubility product of BaSO₄ is \(S^2\), where \(S\) is the solubility of BaSO₄. - From the dissociation: \[ \text{BaSO}_4 (s) \rightleftharpoons \text{Ba}^{2+} (aq) + \text{SO}_4^{2-} (aq) \] - If the solubility of BaSO₄ is \(S\), then: \[ [\text{Ba}^{2+}] = S \quad \text{and} \quad [\text{SO}_4^{2-}] = S \] - Thus, the Ksp expression becomes: \[ K_{sp} = S \cdot S = S^2 \] **Conclusion for Statement 2:** - Statement 2 is **true**. --- ### Final Conclusion: - Statement 1 is false, and Statement 2 is true. Therefore, the correct option is **D**.
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