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STATEMENT-1: For a hypotherical equlibri...

STATEMENT-1: For a hypotherical equlibrium, `AB_(2)(g)hArr2AB(g), K_(rho)` is always greater than `K_(c).`
STATEMENT-2: Relation of `K_(rho)and K_(c)` will be `K_(rho)=K_(c)(RT)Delta_(ng).`

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-10

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-10

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we need to analyze both statements and the relationship between \( K_p \) and \( K_c \). ### Step-by-Step Solution: **Step 1: Understand the Equilibrium Reaction** The equilibrium reaction given is: \[ AB_2(g) \rightleftharpoons 2AB(g) \] This indicates that one mole of \( AB_2 \) dissociates into two moles of \( AB \). **Step 2: Define \( K_p \) and \( K_c \)** - \( K_p \) is the equilibrium constant expressed in terms of partial pressures. - \( K_c \) is the equilibrium constant expressed in terms of molar concentrations. **Step 3: Determine \( \Delta n \)** Calculate the change in the number of moles of gas (\( \Delta n \)): - Moles of products = 2 (from \( 2AB \)) - Moles of reactants = 1 (from \( AB_2 \)) \[ \Delta n = \text{Moles of products} - \text{Moles of reactants} = 2 - 1 = 1 \] **Step 4: Relate \( K_p \) and \( K_c \)** The relationship between \( K_p \) and \( K_c \) is given by the formula: \[ K_p = K_c (RT)^{\Delta n} \] Substituting \( \Delta n = 1 \): \[ K_p = K_c (RT)^{1} = K_c (RT) \] **Step 5: Analyze the Relationship** Since \( R \) (the gas constant) and \( T \) (temperature) are both positive values, it follows that: \[ K_p > K_c \] This confirms that for the given equilibrium, \( K_p \) is always greater than \( K_c \). **Step 6: Evaluate the Statements** - **Statement 1**: \( K_p \) is always greater than \( K_c \) → This is **True**. - **Statement 2**: The relation \( K_p = K_c (RT)^{\Delta n} \) is correct → This is **True**. ### Conclusion Both statements are correct, and Statement 2 correctly explains Statement 1. ### Final Answer Both Statement 1 and Statement 2 are correct, and Statement 2 is the correct explanation for Statement 1. ---
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