A source of light of 100 V will produce 6 kJ energy if 10 ampere current is passed for t sec. The value of t is

Answer

To solve the problem, we need to find the value of \( t \) given that a source of light produces 6 kJ of energy when a current of 10 A is passed through it at a voltage of 100 V.

### Step-by-Step Solution:

1. **Understanding the Given Values**:
- Voltage (\( V \)) = 100 V
- Current (\( I \)) = 10 A
- Energy (\( E \)) = 6 kJ = 6000 J (since 1 kJ = 1000 J)

2. **Formula for Electrical Energy**:
The energy produced by an electrical source can be calculated using the formula:
\[ E = V \times I \times t \]
where \( E \) is energy in joules, \( V \) is voltage in volts, \( I \) is current in amperes, and \( t \) is time in seconds.

3. **Rearranging the Formula to Solve for \( t \)**:
We can rearrange the formula to solve for \( t \):
\[ t = \frac{E}{V \times I} \]

4. **Substituting the Values**:
Now, substitute the known values into the equation:
\[ t = \frac{6000 \, \text{J}}{100 \, \text{V} \times 10 \, \text{A}} \]

5. **Calculating the Denominator**:
Calculate the denominator:
\[ 100 \, \text{V} \times 10 \, \text{A} = 1000 \, \text{W} \]

6. **Calculating \( t \)**:
Now, substitute back into the equation:
\[ t = \frac{6000 \, \text{J}}{1000 \, \text{W}} = 6 \, \text{s} \]

### Final Answer:
The value of \( t \) is **6 seconds**.

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