The complex `K_(3)[Fe(CN)_(6)]` furnishes

Options

A. 2 ions
B. 3 ions
C. 4 ions
D. 5 ions

Answer

To solve the question regarding the complex \( K_3[Fe(CN)_6] \) and the number of ions it furnishes in solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Components of the Complex:**
The complex \( K_3[Fe(CN)_6] \) consists of:
- 3 potassium ions (\( K^+ \))
- 1 complex ion \( [Fe(CN)_6]^{3-} \)

2. **Dissociation in Aqueous Solution:**
When \( K_3[Fe(CN)_6] \) is dissolved in water, it dissociates into its constituent ions:
\[ K_3[Fe(CN)_6] \rightarrow 3K^+ + [Fe(CN)_6]^{3-} \]

3. **Count the Total Number of Ions:**
From the dissociation:
- We have 3 potassium ions (\( K^+ \))
- We have 1 complex ion \( [Fe(CN)_6]^{3-} \)

Therefore, the total number of ions produced is:
\[ 3 + 1 = 4 \text{ ions} \]

4. **Conclusion:**
The complex \( K_3[Fe(CN)_6] \) furnishes a total of 4 ions when dissolved in an aqueous medium.

### Final Answer:
The correct option is that the complex furnishes **4 ions**.

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