Total number of electrons donated by ligands to platinum ion in `[Pt(en)_(2)Cl_(2)]` is

Options

A. 8
B. 10
C. 12
D. 14

Answer

To determine the total number of electrons donated by ligands to the platinum ion in the complex \([Pt(en)_2Cl_2]\), we can follow these steps:

### Step 1: Identify the ligands in the complex
The ligands in the complex \([Pt(en)_2Cl_2]\) are:
- Ethylenediamine (en), which is a bidentate ligand.
- Chloride ions (Cl), which are monodentate ligands.

### Step 2: Determine the number of electrons donated by each ligand
1. **Ethylenediamine (en)**:
- As a bidentate ligand, each ethylenediamine molecule donates 2 pairs of electrons (one pair from each nitrogen atom).
- Therefore, each en donates \(2 \times 2 = 4\) electrons.
- Since there are 2 ethylenediamine ligands, the total contribution from en ligands is:
\[ 4 \text{ electrons} \times 2 = 8 \text{ electrons} \]

2. **Chloride ions (Cl)**:
- Each chloride ion donates 1 pair of electrons (1 lone pair).
- Therefore, each Cl donates 2 electrons.
- Since there are 2 chloride ions, the total contribution from Cl ligands is:
\[ 2 \text{ electrons} \times 2 = 4 \text{ electrons} \]

### Step 3: Calculate the total number of electrons donated
Now, we can sum the contributions from both types of ligands:
\[ \text{Total electrons} = \text{Electrons from en} + \text{Electrons from Cl} \]
\[ \text{Total electrons} = 8 + 4 = 12 \text{ electrons} \]

### Final Answer
The total number of electrons donated by ligands to the platinum ion in \([Pt(en)_2Cl_2]\) is **12**.

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