The complex `[Cr(H_(2)O)_(5)Cl]Br and [Cr(H_(2)O)_(5)Br]Cl` show

Options

A. Linkage isomerism
B. Ionisation isomerism
C. Hydrate isomerism
D. Co-ordination isomerism

Answer

To solve the question regarding the complexes \([Cr(H_2O)_5Cl]Br\) and \([Cr(H_2O)_5Br]Cl\), we need to analyze the nature of these complexes and the type of isomerism they exhibit.

### Step-by-Step Solution:

1. **Identify the Complexes**:
We have two complexes:
- \([Cr(H_2O)_5Cl]Br\)
- \([Cr(H_2O)_5Br]Cl\)

2. **Analyze the Composition**:
- In the first complex, \([Cr(H_2O)_5Cl]Br\), the chromium ion is coordinated to five water molecules and one chloride ion, with bromide as the counter ion.
- In the second complex, \([Cr(H_2O)_5Br]Cl\), the chromium ion is coordinated to five water molecules and one bromide ion, with chloride as the counter ion.

3. **Identify the Ligands and Counter Ions**:
- In the first complex, the ligands are \(H_2O\) and \(Cl^-\), while \(Br^-\) is the counter ion.
- In the second complex, the ligands are \(H_2O\) and \(Br^-\), while \(Cl^-\) is the counter ion.

4. **Determine the Type of Isomerism**:
- The key observation is that there is an exchange of the counter ion and the ligand between the two complexes. In the first complex, \(Cl^-\) is a ligand, while in the second complex, \(Br^-\) is a ligand.
- This exchange indicates that the two complexes differ in the identity of the counter ion and the ligand.

5. **Conclusion**:
- The type of isomerism exhibited by these complexes is **ionization isomerism** because the complexes differ in the way the counter ions and ligands are arranged.

### Final Answer:
The correct type of isomerism shown by the complexes \([Cr(H_2O)_5Cl]Br\) and \([Cr(H_2O)_5Br]Cl\) is **ionization isomerism**.

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