How many `sp^(3)` hybridised atoms are there in one molecule of `CuSO_(4).5H_(2)O` ?

Answer

To determine how many sp³ hybridized atoms are present in one molecule of CuSO₄·5H₂O, we can follow these steps:

### Step 1: Identify the components of CuSO₄·5H₂O
CuSO₄·5H₂O consists of one copper ion (Cu²⁺), one sulfate ion (SO₄²⁻), and five water molecules (H₂O).

### Step 2: Analyze the hybridization of the atoms
- **Copper (Cu)**: In CuSO₄, copper typically exhibits a +2 oxidation state and coordinates with water molecules. However, copper itself does not hybridize in the context of this question, as we are focusing on the hybridization of other atoms.

- **Sulfate ion (SO₄²⁻)**: The sulfate ion has a tetrahedral geometry. The sulfur atom in the sulfate ion is sp³ hybridized because it is bonded to four oxygen atoms.

- **Water molecules (H₂O)**: Each water molecule has an oxygen atom that is sp³ hybridized. In CuSO₄·5H₂O, there are five water molecules, contributing five sp³ hybridized oxygen atoms.

### Step 3: Count the sp³ hybridized atoms
- From the sulfate ion (SO₄²⁻):
- 1 sp³ hybridized sulfur atom
- 4 sp³ hybridized oxygen atoms

- From the five water molecules:
- 5 sp³ hybridized oxygen atoms (one from each water molecule)

### Step 4: Total count of sp³ hybridized atoms
Now, we can sum the sp³ hybridized atoms:
- Sulfur: 1
- Oxygen from sulfate: 4
- Oxygen from water: 5

Total = 1 (S) + 4 (O from SO₄) + 5 (O from H₂O) = **10 sp³ hybridized atoms**.

### Final Answer
There are **10 sp³ hybridized atoms** in one molecule of CuSO₄·5H₂O.

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