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Strongest C-O bond is present in...

Strongest C-O bond is present in

A

`Fe(CO)_(5)`

B

`Mn(CO)_(6)^(+)`

C

`Cr(CO)_(6)`

D

`V(CO)_(6)^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compound has the strongest C-O bond, we need to analyze the oxidation states of the metals in the given coordination compounds. The strength of the C-O bond in metal carbonyl complexes is influenced by the oxidation state of the metal. ### Step-by-Step Solution: 1. **Identify the Compounds**: We need to look at the compounds provided in the question. Let's denote them as Compound A, Compound B, Compound C, and Compound D. 2. **Determine the Oxidation States**: - For each compound, determine the oxidation state of the metal. - For example: - In Compound A, if the metal is Manganese (Mn), its oxidation state is +1. - In Compound B, if the metal is Chromium (Cr), its oxidation state is 0. - In Compound C, if the metal is Vanadium (V), its oxidation state is -1. - In Compound D, if the metal is Manganese again, its oxidation state is 0. 3. **Understand the Relationship Between Oxidation State and Bond Strength**: - As the oxidation state of the metal increases, the ability of the metal to back-donate electron density to the π* orbitals of CO increases. This back-donation weakens the C-O bond. - Conversely, a lower oxidation state means less back-donation and thus a stronger C-O bond. 4. **Analyze the Oxidation States**: - From the oxidation states determined: - Mn (+1) in Compound A - Cr (0) in Compound B - V (-1) in Compound C - Mn (0) in Compound D - The highest oxidation state is +1 for Manganese in Compound A. 5. **Conclusion**: - Since the C-O bond strength is inversely related to the oxidation state of the metal, the compound with the highest oxidation state (Mn in +1 state) will have the strongest C-O bond. - Therefore, the strongest C-O bond is present in the compound with Manganese in the +1 oxidation state. ### Final Answer: The strongest C-O bond is present in the compound with Manganese in the +1 oxidation state. ---
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