The structure of 4-Methylpent-2-en-1-ol is

Options

A. `CH_(3)CH_(2)CH=CH-CH_(2)-OH`
B. `(CH_(3))_(2)CH=CHCH_(2)CH_(2)OH`
C. `(CH_(3))_(2)CH CH=CH CH_(2)OH`
D. `CH_(3)CH(OH)CH-CH=C(CH_(3))_(2)`

Answer

To determine the structure of 4-Methylpent-2-en-1-ol, we will follow the systematic approach of naming organic compounds, which includes identifying the substituents, the main carbon chain, and the functional groups.

### Step-by-Step Solution:

1. **Identify the Root Word and Number of Carbons:**
- The root word "pent" indicates that the longest carbon chain contains 5 carbon atoms.
- Therefore, we will start by drawing a straight chain of 5 carbon atoms.

**Hint:** The root word gives you the number of carbon atoms in the longest chain.

2. **Number the Carbon Chain:**
- Number the carbon chain from one end to the other. We can number them as follows:
- C1, C2, C3, C4, C5

**Hint:** Numbering the carbon chain helps in identifying the positions of substituents and functional groups.

3. **Identify the Functional Groups:**
- The suffix "1-ol" indicates that there is an alcohol (–OH) group attached to the first carbon (C1).
- The "2-ene" indicates that there is a double bond between C2 and C3.

**Hint:** The suffix tells you the functional groups and their positions in the molecule.

4. **Add the Alcohol Group:**
- Place the –OH group on C1. This gives us:
- C1: OH
- C2: C
- C3: C
- C4: C
- C5: C

**Hint:** Ensure that the functional group is placed according to the numbering system.

5. **Add the Double Bond:**
- Place a double bond between C2 and C3. This means that C2 and C3 will be connected by a double bond.

**Hint:** The position of the double bond is crucial for the structure and is indicated by the "ene" in the name.

6. **Add the Methyl Group:**
- The prefix "4-methyl" indicates that there is a methyl (–CH3) group attached to C4.
- Therefore, add a –CH3 group to C4.

**Hint:** Substituents should be placed on the correct carbon as indicated by their position in the name.

7. **Complete the Structure:**
- Now, we need to complete the valency of each carbon atom with hydrogen atoms (H) to ensure that each carbon has four bonds:
- C1: OH
- C2: C (double bond with C3)
- C3: C (double bond with C2)
- C4: C (with a –CH3 group)
- C5: C

The completed structure will look like this:
- C1: OH
- C2: C (double bond with C3)
- C3: C (double bond with C2)
- C4: C (with –CH3)
- C5: C

The final structure can be represented as:
- CH3-CH=CH-CH(CH3)-CH2OH

**Hint:** Make sure to check that all carbons have four bonds satisfied.

### Final Structure:
The structure of 4-Methylpent-2-en-1-ol is:
- CH3-CH=CH-CH(CH3)-CH2OH