Which of the following has a bond formed by overlap of `sp^(3)-sp`, hybrid orbitals?

Options

A. `CH_(3)-C-=C-CH_(3)`
B. `CH_(3)-CH=CH-CH_(3)`
C. `CH_(2)=CH-CH=CH_(2)`
D. `CH_2=CH_2`

Answer

To determine which of the given options has a bond formed by the overlap of `sp^3` and `sp` hybrid orbitals, we need to analyze the hybridization of the carbon atoms in each option.

### Step-by-Step Solution:

1. **Understanding Hybridization**:
- Carbon can exhibit different types of hybridization based on the number of sigma and pi bonds it forms:
- **sp³ hybridization**: Involves four sigma bonds (e.g., in alkanes).
- **sp² hybridization**: Involves three sigma bonds and one pi bond (e.g., in alkenes).
- **sp hybridization**: Involves two sigma bonds and two pi bonds (e.g., in alkynes).

2. **Analyzing the Options**:
- We will analyze each option to identify the hybridization of the carbon atoms involved in the bond.

3. **Option A**: CH₃-C≡C-CH₃
- The first carbon (CH₃) is bonded to three hydrogens and one carbon (C≡C), indicating it has four sigma bonds. Therefore, it is **sp³ hybridized**.
- The second carbon (C≡C) is involved in a triple bond with another carbon. This carbon has two sigma bonds and two pi bonds, indicating it is **sp hybridized**.
- **Conclusion**: This option contains one carbon with `sp³` hybridization and another with `sp` hybridization.

4. **Option B**: CH₃-CH=CH-CH₃
- The first carbon (CH₃) is **sp³ hybridized**.
- The second carbon (CH) is involved in a double bond (C=CH), making it **sp² hybridized**.
- The third carbon (CH) is also **sp² hybridized**.
- **Conclusion**: This option does not contain both `sp³` and `sp` hybridized carbons.

5. **Option C**: CH₂=CH-CH=CH₂
- All carbons in this structure are involved in double bonds, indicating they are all **sp² hybridized**.
- **Conclusion**: This option does not contain both `sp³` and `sp` hybridized carbons.

6. **Option D**: CH₂=CH-CH₂-CH₃
- The first carbon (CH₂) is **sp² hybridized** due to the double bond.
- The second carbon (CH) is also **sp² hybridized**.
- The third carbon (CH₂) is **sp³ hybridized**.
- **Conclusion**: This option contains one carbon with `sp³` hybridization but does not have an `sp` hybridized carbon.

### Final Answer:
The correct option that contains a bond formed by the overlap of `sp³` and `sp` hybrid orbitals is **Option A: CH₃-C≡C-CH₃**.