Which of the following can exhibit geometrical isomerism?

Options

A. `C_(6)H_(4)CH=N-OH`
B.
C. `(CH_(3))_(2)C=C(CH_(3))_(2)`
D.

Answer

To determine which of the given compounds can exhibit geometrical isomerism, we need to follow these steps:

### Step 1: Understand Geometrical Isomerism
Geometrical isomerism occurs when there is restricted rotation around a bond, typically a double bond or in cyclic compounds. This leads to different spatial arrangements of atoms or groups.

**Hint:** Look for double bonds or cyclic structures in the compounds you are analyzing.

### Step 2: Analyze Each Compound
1. **Aldoxime (C6H4CH=NOH)**: This compound has a double bond between carbon and nitrogen (C=N). There is restricted rotation around this bond, allowing for different arrangements of the groups attached to the nitrogen and carbon. Therefore, this compound can exhibit geometrical isomerism.

**Hint:** Check for double bonds and see if different groups can be arranged differently around them.

2. **Cyclohexane**: Cyclohexane consists of single bonds (C-C and C-H). Since there is free rotation around these single bonds, it cannot exhibit geometrical isomerism.

**Hint:** Single bonds allow for rotation; thus, geometrical isomerism is not possible.

3. **Compound with C=C and CH3 groups**: If this compound has a double bond between two carbon atoms and both carbon atoms are bonded to identical groups (like CH3), it cannot exhibit geometrical isomerism because there are no different groups to create distinct spatial arrangements.

**Hint:** If all substituents around a double bond are the same, geometrical isomerism cannot occur.

4. **Another compound with a double bond and different groups**: If there are different groups attached to the double bond, this compound can exhibit cis-trans isomerism. For example, if there are two methyl groups on one side of the double bond, it will be cis; if they are on opposite sides, it will be trans.

**Hint:** Look for different groups on either side of a double bond to identify potential for cis-trans isomerism.

### Step 3: Conclusion
Based on the analysis:
- **Aldoxime (C6H4CH=NOH)** can exhibit geometrical isomerism.
- **Cyclohexane** cannot exhibit geometrical isomerism.
- The compound with C=C and CH3 groups cannot exhibit geometrical isomerism if both groups are the same.
- The compound with different groups around a double bond can exhibit cis-trans isomerism.

Thus, the correct answers are the compounds that can exhibit geometrical isomerism, which are **A (Aldoxime)** and potentially another compound with different groups around a double bond.

**Final Answer:** The compounds that can exhibit geometrical isomerism are A (Aldoxime) and the compound with different groups around a double bond.