Statement-1: p-Nitroaniline is more polar than nitrobenzene
and
Statement-2: Nitro group has -M effect.

(a) Statement-1 is true, Statement-2 is true, Statement-2 is a correct explanation for Statement-1
(b) Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation for Statement -1
(c) Statement -1 is true, Statement -2 is false
(d) Statement -1 is false, Statement -2 is true

Answer

To solve the given question, we need to evaluate the two statements regarding p-nitroaniline and nitrobenzene and determine their validity and relationship.

### Step 1: Analyze Statement 1
**Statement 1:** p-Nitroaniline is more polar than nitrobenzene.

- **Polarity Consideration:**
- Nitrobenzene has a nitro group (-NO2) which is an electron-withdrawing group. Its dipole moment is primarily due to this nitro group.
- p-Nitroaniline contains both a nitro group (-NO2) and an amino group (-NH2). The amino group is an electron-donating group and contributes to the overall dipole moment.
- The presence of both groups in p-nitroaniline results in a larger net dipole moment compared to nitrobenzene, as the -NH2 group can donate electron density towards the ring while the -NO2 group withdraws electron density.

**Conclusion for Statement 1:** p-Nitroaniline is indeed more polar than nitrobenzene. Therefore, Statement 1 is **true**.

### Step 2: Analyze Statement 2
**Statement 2:** The nitro group has a -M effect.

- **Understanding -M Effect:**
- The -M (minus mesomeric) effect refers to the ability of a substituent to withdraw electron density through resonance. The nitro group (-NO2) is known to withdraw electron density from the aromatic ring due to its electronegative nature.
- This effect is consistent with the behavior of the nitro group in aromatic compounds, where it stabilizes the positive charge in resonance structures by pulling electron density away.

**Conclusion for Statement 2:** The nitro group does exhibit a -M effect. Therefore, Statement 2 is **true**.

### Step 3: Relationship Between the Statements
- While both statements are true, the -M effect of the nitro group does not directly explain why p-nitroaniline is more polar than nitrobenzene. The increased polarity of p-nitroaniline is due to the combined effects of both the -NO2 and -NH2 groups, rather than solely the -M effect of the nitro group.

### Final Conclusion
- **Correct Option:** Since Statement 1 is true and Statement 2 is true but does not explain Statement 1, the correct answer is:

**(b) Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation for Statement-1.**

---