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0.2g of an organic compound of kjedahl's...

0.2g of an organic compound of kjedahl's analysis gave enough ammonia to just neutralise 20ml of 0.1N `H_(2)SO_(4)` Calculate the % of nitrogen in the compound.

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20 ml of 0.1 `N H_(2)SO_(4)=20ml` of 0.1 N or 0, 1m `NH_(3)`
Now 1000 ml of 1m `NH_(3)` contain 14 g N
1000 ml of 0.1 M `NH_(3)` contain 1.4 g N
`therefore` 20 ml of 0.1 M `NH_(3)` contain `(1.4xx20)/(1000)`
Percentage of `N=(1.4xx20xx100)/(1000xx0.2)=14%`
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