Statement-1: Among isomeric pentanes 2,2-dimethyl propane has highest melting point
and
Statement-2: Due to lowest surface area it will involve weakest van der Waal's interaction.

Answer

To solve the question regarding the statements about isomeric pentanes, we will analyze each statement step by step.

### Step 1: Analyze Statement 1
**Statement 1**: Among isomeric pentanes, 2,2-dimethylpropane has the highest melting point.

- **Explanation**: 2,2-Dimethylpropane is a branched isomer of pentane. The branching in the structure leads to a more compact arrangement of molecules. This compact structure allows for more efficient packing in the solid state, which increases the number of intermolecular interactions (like van der Waals forces) between adjacent molecules. As a result, a higher melting point is observed for 2,2-dimethylpropane compared to its straight-chain and other branched isomers.

### Step 2: Analyze Statement 2
**Statement 2**: Due to the lowest surface area, it will involve the weakest van der Waals interactions.

- **Explanation**: This statement is misleading. While it is true that 2,2-dimethylpropane has a lower surface area compared to its straight-chain counterpart, the key factor affecting melting point is not just surface area but the nature of intermolecular forces. The compact structure of 2,2-dimethylpropane allows for more effective packing and a greater number of van der Waals interactions despite a lower surface area. Therefore, the statement that it involves the weakest van der Waals interactions is incorrect.

### Conclusion
- **Statement 1** is true: 2,2-dimethylpropane does have the highest melting point among isomeric pentanes.
- **Statement 2** is false: The compact structure leads to stronger interactions, not weaker ones.

### Final Answer
- **Statement 1**: True
- **Statement 2**: False