ROH + `SOCl_(2) to `
The final product is

Options

A. Alkyl chloride
B. Alkyl sulphate
C. Alkene
D. Ether

Explanation

To determine the final product of the reaction between an alcohol (ROH) and thionyl chloride (SOCl₂), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are an alcohol (ROH) and thionyl chloride (SOCl₂).

### Step 2: Understand the Reaction Mechanism
When an alcohol reacts with thionyl chloride, the lone pair on the oxygen atom of the alcohol attacks the sulfur atom in SOCl₂. This results in the formation of an intermediate complex.

### Step 3: Formation of Intermediate
The reaction proceeds with the formation of an intermediate where the oxygen atom becomes positively charged (RO⁺) and the sulfur atom is bonded to a chloride ion (Cl⁻) and has a double bond to oxygen (S=O). The structure can be represented as:
\[ R-O^+ - S(=O) - Cl \]

### Step 4: Elimination of Chloride Ion
The negatively charged chloride ion (Cl⁻) can then leave the intermediate, resulting in the formation of an alkyl chloride (RCl). This is accompanied by the release of sulfur dioxide (SO₂) and hydrochloric acid (HCl) as byproducts.

### Step 5: Write the Final Products
The final products of the reaction are:
- Alkyl chloride (RCl)
- Sulfur dioxide (SO₂)
- Hydrochloric acid (HCl)

### Conclusion
The main product of the reaction between ROH and SOCl₂ is **alkyl chloride (RCl)**.

### Final Answer
The final product is **alkyl chloride (RCl)**.

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