`R- overset(18)(OH) + R overset(O)overset(||)(C ) -OH overset(H) (to)`
Products are

Options

A. `R- overset(O)overset(||)(C ) -overset(18)(O) R + H_(2)O`
B. `R- overset(O)overset(||)(C ) -OR +H_(2)^(18)O`
C. `R-overset(O)overset(||)(C ) - OR + H_(2)^(18)O`
D. `R- overset(O)overset(||)(C )- overset(18)(OR) +H_(2)O`

Explanation

To solve the question, we need to analyze the reaction between an alcohol containing oxygen-18 and a carboxylic acid in the presence of an acid catalyst (H⁺). Here’s the step-by-step solution:

### Step 1: Identify the Reactants
We have two reactants:
1. An alcohol (R-OH) that contains oxygen-18 (denoted as R-^18OH).
2. A carboxylic acid (R'-COOH).

### Step 2: Understand the Reaction Mechanism
In the presence of an acid (H⁺), the alcohol can donate a proton (H⁺), and the carboxylic acid can provide a hydroxyl group (OH⁻). This reaction is a typical esterification reaction where an alcohol reacts with a carboxylic acid to form an ester and water.

### Step 3: Formation of the Ester
When the alcohol and carboxylic acid react:
- The hydroxyl group (OH) from the carboxylic acid and the hydrogen (H) from the alcohol combine to form water (H₂O).
- The remaining parts of the alcohol and carboxylic acid combine to form an ester.

The general reaction can be represented as:
\[ \text{R-}^18\text{OH} + \text{R'-COOH} \xrightarrow{\text{H}^+} \text{R'-COOR} + \text{H}_2\text{O} \]

### Step 4: Identify the Products
The product formed is an ester (R'-COOR) where:
- R' is the alkyl group from the carboxylic acid.
- R is the alkyl group from the alcohol, which contains the oxygen-18.

### Step 5: Conclusion
The final products of the reaction are:
1. An ester (R'-COOR) where the oxygen in the ester is the oxygen-18 from the alcohol.
2. Water (H₂O).

Thus, the correct product is R'-COOR with the oxygen-18 incorporated into the ester.