Which one is optically active aromatic ether ?

Options

A.
B.
C.
D.

Explanation

To determine which aromatic ether is optically active, we need to identify if there is a chiral carbon in the given options. A carbon atom is considered chiral if it has four different groups attached to it.

### Step-by-Step Solution:

1. **Understanding Chirality**:
- A carbon atom is chiral if it has four different substituents attached to it. This property is crucial for optical activity.

2. **Analyzing Each Option**:
- **Option 1**: Examine the carbon atom in question.
- Groups attached: Methyl (–CH₃), Ethyl (–C₂H₅), Hydrogen (–H), and an O-phenyl group (–O-C₆H₅).
- Since all four groups are different, this carbon is a chiral center, making this option optically active.

- **Option 2**: Analyze the carbon atom.
- Groups attached: Two Hydrogen atoms (–H) and two other groups.
- Since there are two identical groups (H), this carbon is not a chiral center, hence not optically active.

- **Option 3**: Examine the carbon atom.
- Groups attached: Two Methyl groups (–CH₃) and one H and one other group.
- Again, there are two identical groups (–CH₃), so this carbon is not chiral, making it optically inactive.

- **Option 4**: Analyze the compound.
- This compound does not contain an aromatic ring, so it cannot be classified as an aromatic ether.
- Therefore, this option is incorrect.

3. **Conclusion**:
- The only option that contains a chiral carbon with four different groups is **Option 1**. Thus, it is the only optically active aromatic ether among the given choices.

### Final Answer:
**Option 1 is the correct answer as it is the only optically active aromatic ether.**