An organic compound `ul(A)` react with sodium to form another compound `ul(B)` . The compound `ul(A)` when heated with concentrated `H_(2)SO_(4)` forms diethyl ether . The compound `ul(A)` and `ul(B)` are respectively

Options

A. `C_(3)H_(7) OH ` and `CH_(3) H_(7) ONa`
B. `CH_(3) OH " and " CH_(3) ON a`
C. `C_(2)H_(5)OH " and " C_(2) H_(5)ON a`
D. `C_(2)H _(5)OH " and " CH_(3) ON a`

Explanation

To solve the problem, we need to identify the organic compounds A and B based on the information provided in the question.

### Step-by-Step Solution:

1. **Understanding the Reaction with Sodium**:
- The question states that compound A reacts with sodium to form compound B.
- In organic chemistry, when an alcohol reacts with sodium, it forms an alkoxide. The general reaction can be represented as:
\[ R-OH + Na \rightarrow R-O^-Na^+ \]
- Here, R represents the alkyl group in the alcohol.

2. **Analyzing the Reaction with Concentrated H2SO4**:
- The question also states that compound A, when heated with concentrated sulfuric acid (H₂SO₄), forms diethyl ether.
- The formation of ether from alcohols can be represented as:
\[ 2 R-OH \xrightarrow{H_2SO_4} R-O-R + H_2O \]
- Since we are specifically forming diethyl ether (C₂H₅-O-C₂H₅), we can deduce that compound A must be ethanol (C₂H₅OH).

3. **Identifying Compound A**:
- Based on the above analysis, we conclude that compound A is ethanol (C₂H₅OH).

4. **Identifying Compound B**:
- Since compound A (C₂H₅OH) reacts with sodium to form an alkoxide, we can now determine compound B.
- The reaction of ethanol with sodium gives sodium ethoxide (C₂H₅O^-Na^+), which can be represented as:
\[ C_2H_5OH + Na \rightarrow C_2H_5O^-Na^+ \]
- Therefore, compound B is sodium ethoxide (C₂H₅ONa).

5. **Final Answer**:
- Thus, the compounds A and B are:
- Compound A: C₂H₅OH (Ethanol)
- Compound B: C₂H₅ONa (Sodium ethoxide)

### Conclusion:
The correct answer is:
- Compound A: C₂H₅OH
- Compound B: C₂H₅ONa