Compound (X ) `C_(7)H_(8)O` dissolves in NaOH but not in `NaHCO_(3)` ( X) reacts rapidly with `Br_(2)` to give (Y) `C_(7) H_(5) O Br_(3)` Product structure of X would be

Options

A.
B.
C.
D.

Explanation

To determine the structure of compound (X) with the molecular formula C₇H₈O, we will follow these steps:

### Step 1: Analyze the given information
- The compound (X) has the molecular formula C₇H₈O.
- It dissolves in NaOH but not in NaHCO₃.
- It reacts rapidly with Br₂ to give a product (Y) with the formula C₇H₅OBr₃.

### Step 2: Determine the functional group
Since (X) dissolves in NaOH, it indicates that (X) is likely an alcohol or a phenol. The fact that it does not dissolve in NaHCO₃ suggests that it is not a carboxylic acid, as carboxylic acids typically react with NaHCO₃.

### Step 3: Consider possible structures
Given the molecular formula C₇H₈O, we can consider various isomers:
- Benzyl alcohol (C₆H₅CH₂OH)
- Cresols (ortho, meta, para)
- Other possible phenolic compounds.

### Step 4: Analyze the reaction with Br₂
The rapid reaction with Br₂ suggests that (X) contains an aromatic ring, as alkenes and phenols typically react with bromine. The product (Y) has the formula C₇H₅OBr₃, indicating that three bromine atoms are added to the structure of (X).

### Step 5: Identify the structure of (X)
Considering the information, we can deduce that:
- If (X) is a cresol, it would react with Br₂ to yield a brominated product.
- The structure of (X) could be meta-cresol (C₆H₄(CH₃)OH), which would react with Br₂ to give the product with three bromine atoms.

### Conclusion
The structure of compound (X) is likely meta-cresol (C₆H₄(CH₃)OH), which matches the criteria provided in the question.