Statement -1 : When phenol is treated with `PBr_(3)` is gives bromobenzene.
Statement -2 It is an example of nucleophilic substitution

Options

A. Statement -1 is true ,Statement -2 is True , Statement -2 is a correct explanation for Statement `-1 `
B. Statement -1 is True , Statement -2 is True Statement -2 is NOT a correct explanation for Statement `-1`
C. Statement -1 is True Statement -2 is False
D. Statement -1 is False Statement -2 is True

Explanation

To solve the question regarding the two statements about phenol and its reaction with PBr3, we will analyze each statement step by step.

### Step 1: Analyze Statement 1
**Statement 1:** When phenol is treated with PBr3, it gives bromobenzene.

- **Explanation:** Phenol (C6H5OH) reacts with phosphorus tribromide (PBr3). In this reaction, the hydroxyl group (-OH) of phenol interacts with PBr3. The oxygen atom of the hydroxyl group donates its lone pair to phosphorus, leading to the formation of a more reactive intermediate. This intermediate allows for the bromine atom to replace the hydroxyl group, resulting in the formation of bromobenzene (C6H5Br).

### Step 2: Analyze Statement 2
**Statement 2:** It is an example of nucleophilic substitution.

- **Explanation:** Nucleophilic substitution involves a nucleophile attacking an electrophile, leading to the replacement of a leaving group. In this case, the hydroxyl group (-OH) is a poor leaving group. However, when PBr3 is used, it converts the -OH group into a better leaving group (Br-). The bromide ion (Br-) acts as a nucleophile and attacks the benzene ring, resulting in the substitution of the -OH group with a bromine atom.

### Conclusion
- **Statement 1 is true:** Phenol does indeed react with PBr3 to form bromobenzene.
- **Statement 2 is false:** While the reaction involves substitution, the mechanism does not follow the typical nucleophilic substitution pathway directly because the hydroxyl group is first converted to a better leaving group.

### Final Answer
- **Correct Option:** Statement 1 is true, Statement 2 is false.

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