2g of NaOH and 4.9 g of `H_2SO_4` ​were mixed and volume is made 1 litre. The normality of the resulting solution will be:

Explanation

To find the normality of the resulting solution after mixing 2 g of NaOH and 4.9 g of H₂SO₄ in 1 litre of solution, we can follow these steps:

### Step 1: Calculate the equivalent weight of NaOH
- **Molar mass of NaOH**: Sodium (Na) = 23 g/mol, Oxygen (O) = 16 g/mol, Hydrogen (H) = 1 g/mol
- Therefore, Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
- **n-factor for NaOH**: Since NaOH provides one hydroxide ion (OH⁻), n-factor = 1.
- **Equivalent weight of NaOH** = Molar mass / n-factor = 40 g/mol / 1 = 40 g/equiv.

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