Statement 1: N, N-dimethyl aniline does not react with nitrous acid, whereas aniline react with nitrous acid.
and
Statement 2:N, N-dimethy aniline is more basic than aniline.

Options

A. Statement-1 is true, Statement-2 is true, statement-2 is a correct explanation for statement-4
B. Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-4
C. Statement-1 is true, statement-2 is False
D. Statement-1 is False, Statement-2 is True.

Answer

To analyze the statements given in the question, we will break down each statement and provide a step-by-step explanation.

### Step 1: Understanding the Reactivity with Nitrous Acid

- **Statement 1**: N,N-dimethyl aniline does not react with nitrous acid, whereas aniline reacts with nitrous acid.

- Aniline (C6H5NH2) has an amino group (-NH2) that can be protonated and subsequently react with nitrous acid (HNO2) to form a diazonium salt (C6H5N2+). This reaction occurs because aniline has two hydrogen atoms attached to the nitrogen that can be replaced.

- N,N-dimethyl aniline (C6H5N(CH3)2) has two methyl groups attached to the nitrogen instead of hydrogen atoms. The presence of these methyl groups prevents the formation of a diazonium salt because there are no hydrogen atoms available for substitution. Therefore, N,N-dimethyl aniline does not react with nitrous acid.

### Conclusion for Statement 1:
- **True**: N,N-dimethyl aniline does not react with nitrous acid, while aniline does.

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### Step 2: Understanding Basicity

- **Statement 2**: N,N-dimethyl aniline is more basic than aniline.

- Basicity in amines is influenced by the electron-donating or withdrawing effects of substituents attached to the nitrogen atom. In the case of N,N-dimethyl aniline, the two methyl groups exert a +I (inductive) effect, which increases the electron density on the nitrogen atom. This makes the nitrogen more nucleophilic and thus more basic.

- Aniline, on the other hand, has only one hydrogen atom attached to the nitrogen, which does not provide the same level of electron donation as the two methyl groups in N,N-dimethyl aniline. Therefore, N,N-dimethyl aniline is indeed more basic than aniline.

### Conclusion for Statement 2:
- **True**: N,N-dimethyl aniline is more basic than aniline.

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### Final Conclusion:
Both statements are true, but they are not related to each other. The correct answer is that both statements are true.